Fractional Exponents Simplify Expressions with Roots and Rational Exponents … - MywallpapersMobi

# Fractional Exponents

Also called "Radicals" or "Rational Exponents"

## Whole Number Exponents

First, let us look at whole number exponents :

The exponent of a number says how many times to use the number in a multiplication.

In this example: 82 = 8 × 8 = 64

In words: 82 could be called "8 to the second power", "8 to the power 2" or
simply "8 squared"

Another example: 53 = 5 × 5 × 5 = 125

## Fractional Exponents

But what if the exponent is a fraction?

 An exponent of 12 is actually square rootAn exponent of 13 is cube rootAn exponent of 14 is 4th rootAnd so on!

## Why?

Let’s see why in an example.

First, the Laws of Exponents tell us how to handle exponents when we multiply:

### Example: x2x2 = (xx)(xx) = xxxx = x4

Which shows that x2x2 = x(2+2) = x4

So let us try that with fractional exponents:

### Example: What is 9½ × 9½ ?

9½ × 9½ = 9(½+½) = 9(1) = 9

So 9½ times itself gives 9.

What do we call a number that, when multiplied by itself, gives another number? The square root !

See:

√9 × √9 = 9

And:

9½ × 9½ = 9

So 9½ is the same as √9

## Try Another Fraction

Let us try that again, but with an exponent of one-quarter (1/4):

### Example:

16¼ × 16¼ × 16¼ × 16¼ = 16(¼+¼+¼+¼) = 16(1) = 16

So 16¼ used 4 times in a multiplication gives 16,

and so 16¼ is a 4th root of 16

## General Rule

It worked for ½, it worked with ¼, in fact it works generally:

x1/n = The n-th Root of x

So we can come up with this:

 A fractional exponent like 1/n means to take the n-th root:

### Example: What is 271/3 ?

Answer: 271/3 = 27 = 3

## What About More Complicated Fractions?

What about a fractional exponent like 43/2 ?

That is really saying to do a cube (3) and a square root (1/2), in any order.

Let me explain.

A fraction (like m/n) can be broken into two parts:

• a whole number part (m) , and
• a fraction (1/n) part

So, because m/n = m × (1/n) we can do this:

The order does not matter, so it also works for m/n = (1/n) × m:

And we get this:

 A fractional exponent like m/n means:   Do the m-th power, then take the n-th rootOR Take the n-th root and then do the m-th power

Some examples:

### Example: What is 43/2 ?

43/2 = 43×(1/2) = √(43) = √(4×4×4) = √(64) = 8

or

43/2 = 4(1/2)×3 = (√4)3 = (2)3 = 8

Either way gets the same result.

### Example: What is 274/3 ?

274/3 = 274×(1/3) = (274) = (531441) = 81

or

274/3 = 27(1/3)×4 = (27)4 = (3)4 = 81

It was certainly easier the 2nd way!

## Now … Play With The Graph!

See how smoothly the curve changes when you play with the fractions in this animation, this shows you that this idea of fractional exponents fits together nicely:

Things to try:

• Start with m=1 and n=1, then slowly increase n so that you can see 1/2, 1/3 and 1/4
• Then try m=2 and slide n up and down to see fractions like 2/3 etc
• Now try to make the exponent -1
• Lastly try increasing m, then reducing n, then reducing m, then increasing n: the curve should go around and around

Laws of Exponents
Exponent
Powers of 10

## Simplify Expressions with Roots and Rational Exponents

### Learning Objectives

• Introduction to Roots
• Define and evaluate principal square roots
• Define and evaluate nth roots
• Estimate roots that are not perfect
• Radical Expressions and Rational Exponents
• Define and identify a radical expression
• Convert radicals to expressions with rational exponents
• Convert expressions with rational exponents to their radical equivalent
• Simplify radical expressions using factoring
• Simplify radical expressions using rational exponents and the laws of exponents
• Define $\sqrtx^2=|x|$, and apply it when simplifying radical expressions

Did you know that you can take the 6th root of a number? You have probably heard of a square root, written $\sqrt{}$, but you can also take a third, fourth and even a 5,000th root (if you really had to). In this lesson we will learn how a square root is defined and then we will build on that to form an understanding of nth roots.  We will use factoring and rules for exponents to simplify mathematical expressions that contain roots.

The most common root is the square root. First, we will define what square roots are,  and how you find the square root of a number. Then we will apply similar ideas to define and evaluate nth roots.

Roots are the inverse of exponents, much like multiplication is the inverse of division. Recall how exponents are defined, and written; with an exponent, as words, and as repeated multiplication.

Exponent: $3^2$, $4^5$, $x^3$, $x^\textn$

Name: “Three squared” or “Three to the second power”, “Four to the fifth power”, “x cubed”, “x to the nth power”

Repeated Multiplication: $3\cdot 3$,  $4\cdot 4\cdot 4\cdot 4\cdot 4$,  $x\cdot x\cdot x$,  $\underbracex\cdot x\cdot x…\cdot x_n\text times$.

Conversely,  when you are trying to find the square root of a number (say, 25), you are trying to find a number that can be multiplied by itself to create that original number. In the case of 25, you can find that $5\cdot5=25$, so 5 must be the square root.

## Square Roots

The symbol for the square root is called a radical symbol and looks like this: $\sqrt\,\,\,$. The expression $\sqrt25$ is read “the square root of twenty-five” or “radical twenty-five.” The number that is written under the radical symbol is called the radicand.

The following table shows different radicals and their equivalent written and simplified forms.

$\sqrt36$

“Square root of thirty-six”

$\sqrt36=\sqrt6\cdot 6=6$
$\sqrt100$

“Square root of one hundred”

$\sqrt100=\sqrt10\cdot 10=10$
$\sqrt225$

“Square root of two hundred twenty-five”

$\sqrt225=\sqrt15\cdot 15=15$

Consider $\sqrt25$ again. You may realize that there is another value that, when multiplied by itself, also results in 25. That number is $−5$.

$\beginarrayr5\cdot 5=25\\-5\cdot -5=25\endarray$

By definition, the square root symbol always means to find the positive root, called the principal root. So while $5\cdot5$ and $−5\cdot−5$ both equal 25, only 5 is the principal root. You should also know that zero is special because it has only one square root: itself (since $0\cdot0=0$).

In our first example we will show you how to use radical notation to evaluate principal square roots.

### Example

Find the principal root of each expression.

1. $\sqrt100$
2. $\sqrt16$
3. $\sqrt25+144$
4. $\sqrt49-\sqrt81\\$
5. $-\sqrt81$
6. $\sqrt-9$

1. $\sqrt100=10$ because $10^2=100$
2. $\sqrt\sqrt16=\sqrt4=2$ because $4^2=16$ and $2^2=4$
3. Recall that square roots act as grouping symbols in the order of operations, so addition and subtraction must be performed first when they occur under a radical. $\sqrt25+144=\sqrt169=13$ because $13^2=169$
4. This problem is similar to the last one, but this time subtraction should occur after evaluating the root. Stop and think about why these two problems are different. $\sqrt49-\sqrt81=7 – 9=-2$ because $7^2=49$ and $9^2=81$
5. The negative in front means to take the opposite of the value after you simplify the radical. $-\sqrt81\\-\sqrt9\cdot 9$.  The square root of 81 is 9. Then, take the opposite of 9. $−(9)$

6. $\sqrt-9$, we are looking for a number that when it is squared, returns $-9$. We can try $(-3)^2$, but that will give a positive result, and $3^2$ will also give a positive result. This leads to an important fact –  you cannot find the square root of a negative number.

In the following video we present more examples of how to find a principle square root.

The last example we showed leads to an important characteristic of square roots. You can only take the square root of values that are nonnegative.

Domain of a Square Root
$\sqrt-a$ is not defined for all real numbers, a. Therefore, $\sqrta$ is defined for $a\ge0$

Does $\sqrt25=\pm 5$? Write your ideas and a sentence to defend them in the box below before you look at the answer.

No. Although both $5^2$ and $\left(-5\right)^2$ are $25$, the radical symbol implies only a nonnegative root, the principal square root. The principal square root of 25 is $\sqrt25=5$.

## Cube Roots

We know that $5^2=25, \text and \sqrt25=5$ but what if we want to “undo” $5^3=125, \text or 5^4=625$? We can use higher order roots to answer these questions.

Suppose we know that $a^3=8$. We want to find what number raised to the 3rd power is equal to 8. Since $2^3=8$, we say that 2 is the cube root of 8. In the next example we will evaluate the cube roots of some perfect cubes.

### Example

Evaluate the following:

1. $\sqrt[3]125$
2. $\sqrt[3]-8$
3. $\sqrt[3]27$
Show Solution

1. You can read this as “the third root of 125” or “the cube root of 125.” To evaluate this expression, look for a number that, when multiplied by itself two times (for a total of three identical factors), equals 125. $\text?\cdot\text?\cdot\text?=125$. Since 125 ends in 5, 5 is a good candidate. $5/cdot5/cdot5=125$
2. We want to find a number whose cube is 8. $2\cdot2\cdot2=8$ the cube root of 8 is 2.

3. We want to find a number whose cube is -8. We know 2 is the cube root of 8, so maybe we can try -2. $-2\cdot-2\cdot-2=-8$, so the cube root of -8 is -2. This is different from square roots because multiplying three negative numbers together results in a negative number.

As we saw in the last example,there is one interesting fact about cube roots that is not true of square roots. Negative numbers can’t have real number square roots, but negative numbers can have real number cube roots! What is the cube root of $−8$? $\sqrt[3]-8=-2$ because $-2\cdot -2\cdot -2=-8$. Remember, when you are multiplying an odd number of negative numbers, the result is negative! Consider $\sqrt[3](-1)^3=-1$.

In the following video we show more examples of finding a cube root.

## Nth Roots

The cube root of a number is written with a small number 3, called the index, just outside and above the radical symbol. It looks like $\sqrt[3]{{}}$. This little 3 distinguishes cube roots from square roots which are written without a small number outside and above the radical symbol.

We can apply the same idea to any exponent and it’s corresponding root.  The nth root of $a$ is a number that, when raised to the nth power, gives $a$. For example, $3$ is the 5th root of $243$ because $\left(3\right)^5=243$. If $a$ is a real number with at least one nth root, then the principal nth root of $a$ is the number with the same sign as $a$ that, when raised to the nth power, equals $a$.

The principal nth root of $a$ is written as $\sqrt[n]a$, where $n$ is a positive integer greater than or equal to 2. In the radical expression, $n$ is called the index of the radical.

### Definition: Principal nth Root

If $a$ is a real number with at least one nth root, then the principal nth root of $a$, written as $\sqrt[n]a$, is the number with the same sign as $a$ that, when raised to the nth power, equals $a$. The index of the radical is $n$.

### Example

Evaluate each of the following:

1. $\sqrt[5]-32$
2. $\sqrt[4]81$
3. $\sqrt[8]-1$

1. $\sqrt[5]-32$ Factor 32, because $\left(-2\right)^5=-32 \\ \text$
2. $\sqrt[4]81$. Factoring can help, we know that $9\cdot9=81$ and we can further factor each 9: $\sqrt[4]81=\sqrt[4]3\cdot3\cdot3\cdot3=\sqrt[4]3^4=3$
3. $\sqrt[8]-1$, since we have an 8th root – which is even- with a negative number as the radicand, this root has no real number solutions. In other words, $-1\cdot-1\cdot-1\cdot-1\cdot-1\cdot-1\cdot-1\cdot-1=+1$

In the following video we show more examples of how to evaluate and nth root.

You can find the odd root of a negative number, but you cannot find the even root of a negative number. This means you can evaluate the radicals $\sqrt[3]-81,\ \sqrt[5]-64$, and $\sqrt[7]-2187$, but you cannot evaluate the radicals $\sqrt[{}]-100,\ \sqrt[4]-16$, or $\sqrt[6]-2,500$.

## Estimate Roots

An approach to handling roots that are not perfect (squares, cubes, etc.)  is to approximate them by comparing the values to perfect squares, cubes, or nth roots. Suppose you wanted to know the square root of 17. Let’s look at how you might approximate it.

### Example

Estimate. $\sqrt17$

Show Solution

Think of two perfect squares that surround 17. 17 is in between the perfect squares 16 and 25. So, $\sqrt17$ must be in between $\sqrt16$ and $\sqrt25$.

Determine whether $\sqrt17$ is closer to 4 or to 5 and make another estimate.

$\sqrt16=4$ and $\sqrt25=5$

Since 17 is closer to 16 than 25, $\sqrt17$ is probably about 4.1 or 4.2.

Use trial and error to get a better estimate of $\sqrt17$. Try squaring incrementally greater numbers, beginning with 4.1, to find a good approximation for $\sqrt17$.

$\left(4.1\right)^2$

$\left(4.1\right)^2$ gives a closer estimate than $(4.2)^2$.

$4.1\cdot4.1=16.81\\4.2\cdot4.2=17.64$

Continue to use trial and error to get an even better estimate.

$4.12\cdot4.12=16.9744\\4.13\cdot4.13=17.0569$

$\sqrt17\approx 4.12$

This approximation is pretty close. If you kept using this trial and error strategy you could continue to find the square root to the thousandths, ten-thousandths, and hundred-thousandths places, but eventually it would become too tedious to do by hand.

For this reason, when you need to find a more precise approximation of a square root, you should use a calculator. Most calculators have a square root key $(\sqrt{{}})$ that will give you the square root approximation quickly. On a simple 4-function calculator, you would likely key in the number that you want to take the square root of and then press the square root key.

Try to find $\sqrt17$ using your calculator. Note that you will not be able to get an “exact” answer because $\sqrt17$ is an irrational number, a number that cannot be expressed as a fraction, and the decimal never terminates or repeats. To nine decimal positions, $\sqrt17$ is approximated as 4.123105626. A calculator can save a lot of time and yield a more precise square root when you are dealing with numbers that aren’t perfect squares.

### Example

Approximate $\sqrt[3]30$ and also find its value using a calculator.

Show Solution

Find the cubes that surround 30.

30 is inbetween the perfect cubes 27 and 81.

$\sqrt[3]27=3$ and $\sqrt[3]81=4$, so $\sqrt[3]30$ is between 3 and 4.
Use a calculator.

$\sqrt[3]30\approx3.10723$

By approximation: $3\ge\sqrt[3]30\le4$

Using a calculator: $\sqrt[3]30\approx3.10723$

The following video shows another example of how to estimate a square root.

## Radical Expressions and Rational Exponents

Square roots are most often written using a radical sign, like this, $\sqrt4$. But there is another way to represent them. You can use rational exponents instead of a radical. A rational exponent is an exponent that is a fraction. For example, $\sqrt4$ can be written as $4^\tfrac12$.

Can’t imagine raising a number to a rational exponent? They may be hard to get used to, but rational exponents can actually help simplify some problems. Writing radicals with rational exponents will come in handy when we discuss techniques for simplifying more complex radical expressions.

Radical expressions are expressions that contain radicals. Radical expressions come in many forms, from simple and familiar, such as$\sqrt16$, to quite complicated, as in $\sqrt[3]250x^4y$

## Write an expression with a rational exponent as a radical

Radicals and fractional exponents are alternate ways of expressing the same thing.  In the table below we show equivalent ways to express radicals: with a root, with a rational exponent, and as a principal root.

Exponent Form

Principal Root

$\sqrt16$$16^\tfrac12$4
$\sqrt25$$25^\tfrac12$5
$\sqrt100$$100^\tfrac12$10

Let’s look at some more examples, but this time with cube roots. Remember, cubing a number raises it to the power of three. Notice that in the examples in the table below, the denominator of the rational exponent is the number 3.

Exponent Form

Principal Root

$\sqrt[3]8$$8^\tfrac13$2
$\sqrt[3]8$$125^\tfrac13$5
$\sqrt[3]1000$$1000^\tfrac13$10

These examples help us model a relationship between radicals and rational exponents: namely, that the nth root of a number can be written as either $\sqrt[n]x$ or $x^\frac1n$.

Exponent Form

$\sqrtx$$x^\tfrac12$
$\sqrt[3]x$$x^\tfrac13$
$\sqrt[4]x$$x^\tfrac14$
$\sqrt[n]x$$x^\tfrac1n$

In the table above, notice how the denominator of the rational exponent determines the index of the root. So, an exponent of $\frac12$ translates to the square root, an exponent of $\frac15$ translates to the fifth root or $\sqrt[5]{{}}$, and $\frac18$ translates to the eighth root or $\sqrt[8]{{}}$.

### Example

Express $(2x)^^\frac13$ in radical form.

Show Solution

Rewrite the expression with the fractional exponent as a radical. The denominator of the fraction determines the root, in this case the cube root.

$\sqrt[3]2x$

The parentheses in $\left( 2x \right)^\frac13$ indicate that the exponent refers to everything within the parentheses.

$(2x)^^\frac13=\sqrt[3]2x$

Remember that exponents only refer to the quantity immediately to their left unless a grouping symbol is used. The example below looks very similar to the previous example with one important difference—there are no parentheses! Look what happens.

### Example

Express $2x^^\frac13$ in radical form.

Show Solution

Rewrite the expression with the fractional exponent as a radical. The denominator of the fraction determines the root, in this case the cube root.

$2\sqrt[3]x$

The exponent refers only to the part of the expression immediately to the left of the exponent, in this case x, but not the 2.

$2x^^\frac13=2\sqrt[3]x$

## Write a radical expression as an expression with a rational exponent

Flexibility

We can write radicals with rational exponents, and as we will see when we simplify more complex radical expressions, this can make things easier. Having different ways to express and write algebraic expressions allows us to have flexibility in solving and simplifying them. It is like having a thesaurus when you write, you want to have options for expressing yourself!

### Example

Write $\sqrt[4]81$ as an expression with a rational exponent.

Show Solution

The radical form $\Large\sqrt[4]\,\,\,\,$ can be rewritten as the exponent $\frac14$. Remove the radical and place the exponent next to the base.

$81^\frac14$

$\sqrt[4]81=81^\frac14$

### Example

Express $4\sqrt[3]xy$ with rational exponents.

Show Solution

Rewrite the radical using a rational exponent. The root determines the fraction. In this case, the index of the radical is 3, so the rational exponent will be $\frac13$.

$4(xy)^\frac13$

Since 4 is outside the radical, it is not included in the grouping symbol and the exponent does not refer to it.

$4\sqrt[3]xy=4(xy)^\frac13$

## Rational exponents whose numerator is not equal to one

All of the numerators for the fractional exponents in the examples above were 1. You can use fractional exponents that have numerators other than 1 to express roots, as shown below.

Exponent

$\sqrt9$$9^\frac12$
$\sqrt[3]9^2$$9^\frac23$
$\sqrt[4]9^3$$9^\frac34$
$\sqrt[5]9^2$$9^\frac25$
$\sqrt[n]9^x$$9\fracxn$

To rewrite a radical using a fractional exponent, the power to which the radicand is raised becomes the numerator and the root/ index becomes the denominator.

### Writing Rational Exponents

Any radical in the form $\sqrt[n]a^x$  can be written using a fractional exponent in the form $a^\fracxn$.

The relationship between $\sqrt[n]a^x$and $a^\fracxn$ works for rational exponents that have a numerator of 1 as well. For example, the radical $\sqrt[3]8$ can also be written as $\sqrt[3]8^1$, since any number remains the same value if it is raised to the first power. You can now see where the numerator of 1 comes from in the equivalent form of $8^\frac13$.

In the next example, we practice writing radicals with rational exponents where the numerator is not equal to one.

### Example

1. $\sqrt[3]a^6$
2. $\sqrt[12]16^3$
Show Solution

1.$\sqrt[n]a^x$ can be rewritten as $a^\fracxn$, so in this case $n=3,\text and x=6$, therefore

$\sqrt[3]a^6=a^\frac63$

Simplify the exponent.

$a^\frac63=a^2$

$\sqrt[3]a^6=a^2$

2. $\sqrt[n]a^x$ can be rewritten as $a^\fracxn$, so in this case $n=12,\text and x=3$, therefore

$\sqrt[12]16^3=16^\frac312=16^\frac14$

Simplify the expression using rules for exponents.

$\beginarrayccc16=2^4\\16^\frac14=2^4^\frac14\\=2^4\cdot\frac14\\=2^1=2\endarray$

$\sqrt[12]16^3=2$

In our last example we will rewrite expressions with rational exponents as radicals. This practice will help us when we simplify more complicated radical expressions, and as we learn how to solve radical equations. Typically it is easier to simplify when we use rational exponents, but this exercise is intended to help you understand how the numerator and denominator of the exponent are the exponent of a radicand and index of a radical.

### Example

Rewrite the expressions using a radical.

1. $x^\frac23$
2. $5^\frac47$

1. $x^\frac23$, the numerator is 2 and the denominator is 3, therefore we will have the third root of x squared, $\sqrt[3]x^2$
2. $5^\frac47$, the numerator is 4 and the denominator is 7, so we will have the seventh root of 5 raised to the fourth power. $\sqrt[7]5^4$

In the following video we show more examples of writing radical expressions with rational exponents and expressions with rational exponents as radical expressions.

We will use this notation later, so come back for practice if you forget how to write a radical with a rational exponent.

Radical expressions are expressions that contain radicals. Radical expressions come in many forms, from simple and familiar, such as$\sqrt16$, to quite complicated, as in $\sqrt[3]250x^4y$.

To simplify complicated radical expressions, we can use some definitions and rules from simplifying exponents. Recall the Product Raised to a Power Rule from when you studied exponents. This rule states that the product of two or more non-zero numbers raised to a power is equal to the product of each number raised to the same power. In math terms, it is written $\left(ab\right)^x=a^x\cdotb^x$. So, for example, you can use the rule to rewrite $\left( 3x \right)^2$ as $3^2\cdot x^2=9\cdot x^2=9x^2$.

Now instead of using the exponent 2, let’s use the exponent $\frac12$. The exponent is distributed in the same way.

$\left( 3x \right)^\frac12=3^\frac12\cdot x^\frac12$

And since you know that raising a number to the $\frac12$ power is the same as taking the square root of that number, you can also write it this way.

$\sqrt3x=\sqrt3\cdot \sqrtx$

Look at that—you can think of any number underneath a radical as the product of separate factors, each underneath its own radical.

### A Product Raised to a Power Rule or sometimes called The Square Root of a Product Rule

For any real numbers a and b, $\sqrtab=\sqrta\cdot \sqrtb$.

For example: $\sqrt100=\sqrt10\cdot \sqrt10$, and $\sqrt75=\sqrt25\cdot \sqrt3$

This rule is important because it helps you think of one radical as the product of multiple radicals. If you can identify perfect squares within a radical, as with $\sqrt(2\cdot 2)(2\cdot 2)(3\cdot 3)$, you can rewrite the expression as the product of multiple perfect squares: $\sqrt2^2\cdot \sqrt2^2\cdot \sqrt3^2$.

The square root of a product rule will help us simplify roots that aren’t perfect, as is shown the following example.

### Example

Simplify. $\sqrt63$

Show Solution

63 is not a perfect square so we can use the square root of a product rule to simplify any factors that are perfect squares.
Factor 63 into 7 and 9.
$\sqrt7\cdot 9$
9 is a perfect square, $9=3^2$, therefore we can rewrite the radicand.

$\sqrt7\cdot 3^2$

Using the Product Raised to a Power rule, separate the radical into the product of two factors, each under a radical.
$\sqrt7\cdot \sqrt3^2$
Take the square root of $3^2$.
$\sqrt7\cdot 3$
Rearrange factors so the integer appears before the radical, and then multiply. (This is done so that it is clear that only the 7 is under the radical, not the 3.)
$3\cdot \sqrt7$
$\sqrt63=3\sqrt7$

The final answer $3\sqrt7$ may look a bit odd, but it is in simplified form. You can read this as “three radical seven” or “three times the square root of seven.”

The following video shows more examples of how to simplify square roots that do not have perfect square radicands.

Before we move on to simplifying more complex radicals with variables, we need to learn about an important behavior of square roots with variables in the radicand.

Consider the expression $\sqrtx^2$. This looks like it should be equal to x, right? Let’s test some values for x and see what happens.

In the chart below, look along each row and determine whether the value of x is the same as the value of $\sqrtx^2$. Where are they equal? Where are they not equal?

After doing that for each row, look again and determine whether the value of $\sqrtx^2$ is the same as the value of $\left|x\right|$.

$x$$x^2$$\sqrtx^2$$\left|x\right|$
$−5$2555
$−2$422
0000
63666
101001010

Notice—in cases where x is a negative number, $\sqrtx^2\neqx$! However, in all cases $\sqrtx^2=\left|x\right|$. You need to consider this fact when simplifying radicals with an even index that contain variables, because by definition $\sqrtx^2$ is always nonnegative.

### Taking the Square Root of a Radical Expression

When finding the square root of an expression that contains variables raised to a power, consider that $\sqrtx^2=\left|x\right|$.

Examples: $\sqrt9x^2=3\left|x\right|$, and $\sqrt16x^2y^2=4\left|xy\right|$

We will combine this with the square root of a product rule in our next example to simplify an expression with three variables in the radicand.

### Example

Simplify. $\sqrta^3b^5c^2$

Show Solution

Factor to find variables with even exponents.

$\sqrta^2\cdot a\cdot b^4\cdot b\cdot c^2$

Rewrite $b^4$ as $\left(b^2\right)^2$.

$\sqrta^2\cdot a\cdot (b^2)^2\cdot b\cdot c^2$

Separate the squared factors into individual radicals.

$\sqrta^2\cdot \sqrt(b^2)^2\cdot \sqrtc^2\cdot \sqrta\cdot b$

Take the square root of each radical. Remember that $\sqrta^2=\left| a \right|$.

$\left| a \right|\cdot b^2\cdot \left|c\right|\cdot \sqrta\cdot b$

Simplify and multiply.

$\left| ac \right|b^2\sqrtab$

$\sqrta^3b^5c^2=\left| ac \right|b^2\sqrtab$

### Analysis of the Solution

Why didn’t we write $b^2$ as $|b^2|$?  Because when you square a number, you will always get a positive result, so the principal square root of $\left(b^2\right)^2$ will always be non-negative. One tip for knowing when to apply the absolute value after simplifying any even indexed root is to look at the final exponent on your variable terms.  If the exponent is odd – including 1 – add an absolute value. This applies to simplifying any root with an even index, as we will see in later examples.

In the following video you will see more examples of how to simplify radical expressions with variables.

We will show another example where the simplified expression contains variables with both odd and even powers.

### Example

Simplify. $\sqrt9x^6y^4$

Show Solution

Factor to find identical pairs.

$\sqrt3\cdot 3\cdot x^3\cdot x^3\cdot y^2\cdot y^2$

Rewrite the pairs as perfect squares.

$\sqrt3^2\cdot \left( x^3 \right)^2\cdot \left( y^2 \right)^2$

$\sqrt3^2\cdot \sqrt\left( x^3 \right)^2\cdot \sqrt\left( y^2 \right)^2$

Simplify.

$3x^3y^2$

Because x has an odd power, we will add the absolute value for our final solution.

$3|x^3|y^2$

$\sqrt9x^6y^4=3|x^3|y$

In our next example we will start with an expression written with a rational exponent. You will see that you can use a similar process – factoring and sorting terms into squares – to simplify this expression.

### Example

Simplify. $(36x^4)^\frac12$

Show Solution

Rewrite the expression with the fractional exponent as a radical.

$\sqrt36x^4$

Find the square root of both the coefficient and the variable.

$\beginarrayr \sqrt6^2\cdot x^4\\\sqrt6^2\cdot \sqrtx^4\\\sqrt6^2\cdot \sqrt(x^2)^2\\6\cdotx^2\endarray$

$(36x^4)^\frac12=6x^2$

Here is one more example with perfect squares.

### Example

Simplify. $\sqrt49x^10y^8$

Show Solution

Look for squared numbers and variables. Factor 49 into $7\cdot7$, $x^10$ into $x^5\cdotx^5$, and $y^8$ into $y^4\cdoty^4$.

$\sqrt7\cdot 7\cdot x^5\cdot x^5\cdot y^4\cdot y^4$

Rewrite the pairs as squares.

$\sqrt7^2\cdot (x^5)^2\cdot (y^4)^2$

Separate the squared factors into individual radicals.

$\sqrt7^2\cdot \sqrt(x^5)^2\cdot \sqrt(y^4)^2$

Take the square root of each radical using the rule that $\sqrtx^2=x$.

$7\cdot x^5\cdot y^4$

Multiply.

$7x^5y^4$

$\sqrt49x^10y^8=7|x^5|y^4$

## Simplify cube roots

We can use the same techniques we have used for simplifying square roots to simplify higher order roots. For example to simplify a cube root, the goal is to find factors under the radical that are perfect cubes so that you can take their cube root. We no longer need to be concerned about whether we have identified the principal root since we are now finding cube roots. Focus on finding identical trios of factors as you simplify.

### Example

Simplify. $\sqrt[3]40m^5$

Show Solution

Factor 40 into prime factors.

$\sqrt[3]5\cdot 2\cdot 2\cdot 2\cdot m^5$

Since you are looking for the cube root, you need to find factors that appear 3 times under the radical. Rewrite $2\cdot 2\cdot 2$ as $2^3$.

$\sqrt[3]2^3\cdot 5\cdot m^5$

Rewrite $m^5$ as $m^3\cdot m^2$.

$\sqrt[3]2^3\cdot 5\cdot m^3\cdot m^2$

Rewrite the expression as a product of multiple radicals.

$\sqrt[3]2^3\cdot \sqrt[3]5\cdot \sqrt[3]m^3\cdot \sqrt[3]m^2$

Simplify and multiply.

$2\cdot \sqrt[3]5\cdot m\cdot \sqrt[3]m^2$

$\sqrt[3]40m^5=2m\sqrt[3]5m^2$

Remember that you can take the cube root of a negative expression. In the next example we will simplify a cube root with a negative radicand.

### Example

Simplify. $\sqrt[3]-27x^4y^3$

Show Solution

Factor the expression into cubes.

Separate the cubed factors into individual radicals.

$\beginarrayr\sqrt[3]-1\cdot 27\cdot x^4\cdot y^3\\\sqrt[3](-1)^3\cdot (3)^3\cdot x^3\cdot x\cdot y^3\\\sqrt[3](-1)^3\cdot \sqrt[3](3)^3\cdot \sqrt[3]x^3\cdot \sqrt[3]x\cdot \sqrt[3]y^3\endarray$

Simplify the cube roots.

$-1\cdot 3\cdot x\cdot y\cdot \sqrt[3]x$

$\sqrt[3]-27x^4y^3=-3xy\sqrt[3]x$

You could check your answer by performing the inverse operation. If you are right, when you cube $-3xy\sqrt[3]x$ you should get $-27x^4y^3$.

$\beginarrayl\left( -3xy\sqrt[3]x \right)\left( -3xy\sqrt[3]x \right)\left( -3xy\sqrt[3]x \right)\\-3\cdot -3\cdot -3\cdot x\cdot x\cdot x\cdot y\cdot y\cdot y\cdot \sqrt[3]x\cdot \sqrt[3]x\cdot \sqrt[3]x\\-27\cdot x^3\cdot y^3\cdot \sqrt[3]x^3\\-27x^3y^3\cdot x\\-27x^4y^3\endarray$

You can also skip the step of factoring out the negative one once you are comfortable with identifying cubes.

### Example

Simplify. $\sqrt[3]-24a^5$

Show Solution

Factor $−24$ to find perfect cubes. Here, $−1$ and 8 are the perfect cubes.

$\sqrt[3]-1\cdot 8\cdot 3\cdot a^5$

Factor variables. You are looking for cube exponents, so you factor $a^5$ into $a^3$ and $a^2$.

$\sqrt[3](-1)^3\cdot 2^3\cdot 3\cdot a^3\cdot a^2$

Separate the factors into individual radicals.

$\sqrt[3](-1)^3\cdot \sqrt[3]2^3\cdot \sqrt[3]a^3\cdot \sqrt[3]3\cdot a^2$

Simplify, using the property $\sqrt[3]x^3=x$.

$-1\cdot 2\cdot a\cdot \sqrt[3]3\cdot a^2$

This is the simplest form of this expression; all cubes have been pulled out of the radical expression.

$-2a\sqrt[3]3a^2$

$\sqrt[3]-24a^5=-2a\sqrt[3]3a^2$

You can check your answer by squaring it to be sure it equals $100x^2y^4$.

In the following video we show more examples of simlifying cube roots.

## Simplifying fourth roots

Now let’s move to simplifying fourth degree roots.  No matter what root you are simplifying, the same idea applies, find cubes for cube roots, powers of four for fourth roots, etc. Recall that when your simplified expression contains an even indexed radical and a variable factor with an odd exponent, you need to apply an absolute value.

### Example

Simplify. $\sqrt[4]81x^8y^3$

Show Solution

Rewrite the expression.

$\sqrt[4]81\cdot \sqrt[4]x^8\cdot \sqrt[4]y^3$

$\sqrt[4]3\cdot 3\cdot 3\cdot 3\cdot \sqrt[4]x^2\cdot x^2\cdot x^2\cdot x^2\cdot \sqrt[4]y^3$

Simplify.

$\beginarrayr\sqrt[4]3^4\cdot \sqrt[4](x^2)^4\cdot \sqrt[4]y^3\\3\cdot x^2\cdot \sqrt[4]y^3\endarray$

$\sqrt[4]81x^8y^3=3x^2\sqrt[4]y^3$

An alternative method to factoring is to rewrite the expression with rational exponents, then use the rules of exponents to simplify.  You may find that you prefer one method over the other. Either way, it is nice to have options. We will show the last example again, using this idea.

### Example

Simplify. $\sqrt[4]81x^8y^3$

Show Solution

Rewrite the radical using rational exponents.

$(81x^8y^3)^\frac14$

Use the rules of exponents to simplify the expression.

$\beginarrayr81^\frac14\cdot x^\frac84\cdot y^\frac34\\(3\cdot 3\cdot 3\cdot 3)^\frac14x^2y^\frac34\\(3^4)^\frac14x^2y^\frac34\\3x^2y^\frac34\endarray$

Change the expression with the rational exponent back to radical form.

$3x^2\sqrt[4]y^3$

$\sqrt[4]81x^8y^3=3x^2\sqrt[4]y^3$

In the following video we show another example of how to simplify a fourth and fifth root.

For our last example, we will simplify a more complicated expression, $\large\frac10b^2c^2c\sqrt[3]8b^4$. This expression has two variables, a fraction, and a radical. Let’s take it step-by-step and see if using fractional exponents can help us simplify it.
We will start by simplifying the denominator, since this is where the radical sign is located. Recall that an exponent in the denominator or a fraction can be rewritten as a negative exponent.

### Example

Simplify. $\large\frac10b^2c^2c\sqrt[3]8b^4$

Show Solution

Separate the factors in the denominator.

$\frac10b^2c^2c\cdot \sqrt[3]8\cdot \sqrt[3]b^4$

Take the cube root of 8, which is 2.

$\frac10b^2c^2c\cdot 2\cdot \sqrt[3]b^4$

Rewrite the radical using a fractional exponent.

$\frac10b^2c^2c\cdot 2\cdot b^\frac43$

Rewrite the fraction as a series of factors in order to cancel factors (see next step).

$\frac102\cdot \fracc^2c\cdot \fracb^2b^\frac43$

Simplify the constant and c factors.

$5\cdot c\cdot \fracb^2b^\frac43$

Use the rule of negative exponents, nx=$\frac1n^x$, to rewrite $\frac1b^\tfrac43$ as $b^-\tfrac43$.

$5cb^2b^-\ \frac43$

Combine the b factors by adding the exponents.

$5cb^\frac23$

Change the expression with the fractional exponent back to radical form. By convention, an expression is not usually considered simplified if it has a fractional exponent or a radical in the denominator.

$5c\sqrt[3]b^2$

$\frac10b^2c^2c\sqrt[3]8b^4=5c\sqrt[3]b^2$

Well, that took a while, but you did it. You applied what you know about fractional exponents, negative exponents, and the rules of exponents to simplify the expression.

In our last video we show how to use rational exponents to simplify radical expressions.

## Summary

A radical expression is a mathematical way of representing the nth root of a number. Square roots and cube roots are the most common radicals, but a root can be any number. To simplify radical expressions, look for exponential factors within the radical, and then use the property $\sqrt[n]x^n=x$ if n is odd, and $\sqrt[n]x^n=\left| x \right|$ if n is even to pull out quantities. All rules of integer operations and exponents apply when simplifying radical expressions.

The steps to consider when simplifying a radical are outlined below.

• If n is odd, $\sqrt[n]x^n=x$.
• If n is even, $\sqrt[n]x^n=\left| x \right|$. (The absolute value accounts for the fact that if x is negative and raised to an even power, that number will be positive, as will the nth principal root of that number.)
Any radical in the form $\sqrt[n]a^x$  can be written using a fractional exponent in the form $a^\fracxn$. Rewriting radicals using fractional exponents can be useful in simplifying some radical expressions. When working with fractional exponents, remember that fractional exponents are subject to all of the same rules as other exponents when they appear in algebraic expressions.